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10=-3y^2=
We move all terms to the left:
10-(-3y^2)=0
We get rid of parentheses
3y^2+10=0
a = 3; b = 0; c = +10;
Δ = b2-4ac
Δ = 02-4·3·10
Δ = -120
Delta is less than zero, so there is no solution for the equation
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