10=-6(8+4n)=2(2n-1

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Solution for 10=-6(8+4n)=2(2n-1 equation:



10=-6(8+4n)=2(2n-1
We move all terms to the left:
10-(-6(8+4n))=0
We add all the numbers together, and all the variables
-(-6(4n+8))+10=0
We calculate terms in parentheses: -(-6(4n+8)), so:
-6(4n+8)
We multiply parentheses
-24n-48
Back to the equation:
-(-24n-48)
We get rid of parentheses
24n+48+10=0
We add all the numbers together, and all the variables
24n+58=0
We move all terms containing n to the left, all other terms to the right
24n=-58
n=-58/24
n=-2+5/12

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