10=-8y+5(y-4)

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Solution for 10=-8y+5(y-4) equation: 



10=-8y+5(y-4)

We move all terms to the left:

10-(-8y+5(y-4))=0



We calculate terms in parentheses: -(-8y+5(y-4)), so:

-8y+5(y-4)

We multiply parentheses

-8y+5y-20

We add all the numbers together, and all the variables

-3y-20

Back to the equation:

-(-3y-20)



We get rid of parentheses

3y+20+10=0

We add all the numbers together, and all the variables

3y+30=0

We move all terms containing y to the left, all other terms to the right

3y=-30

y=-30/3

y=-10

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