10=1/2(y-40)

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Solution for 10=1/2(y-40) equation:



10=1/2(y-40)
We move all terms to the left:
10-(1/2(y-40))=0
Domain of the equation: 2(y-40))!=0
y∈R
We multiply all the terms by the denominator
-(1+10*2(y-40))=0
We calculate terms in parentheses: -(1+10*2(y-40)), so:
1+10*2(y-40)
determiningTheFunctionDomain 10*2(y-40)+1
Wy multiply elements
20y(y+1
Back to the equation:
-(20y(y+1)
We calculate terms in parentheses: -(20y(y+1), so:
20y(y+1
We calculate terms in parentheses: -(20y(y+1), so:
20y(y+1
We calculate terms in parentheses: -(20y(y+1), so:
20y(y+1
We calculate terms in parentheses: -(20y(y+1), so:
20y(y+1
We calculate terms in parentheses: -(20y(y+1), so:
20y(y+1
We calculate terms in parentheses: -(20y(y+1), so:
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We calculate terms in parentheses: -(20y(y+1), so:
20y(y+1
We calculate terms in parentheses: -(20y(y+1), so:
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We calculate terms in parentheses: -(20y(y+1), so:
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We calculate terms in parentheses: -(20y(y+1), so:
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We calculate terms in parentheses: -(20y(y+1), so:
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We calculate terms in parentheses: -(20y(y+1), so:
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We calculate terms in parentheses: -(20y(y+1), so:
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We calculate terms in parentheses: -(20y(y+1), so:
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