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10=1/2p(p-1)
We move all terms to the left:
10-(1/2p(p-1))=0
Domain of the equation: 2p(p-1))!=0We multiply all the terms by the denominator
p∈R
-(1+10*2p(p-1))=0
We calculate terms in parentheses: -(1+10*2p(p-1)), so:
1+10*2p(p-1)
determiningTheFunctionDomain 10*2p(p-1)+1
Wy multiply elements
20p(p+1
Back to the equation:
-(20p(p+1)
We calculate terms in parentheses: -(20p(p+1), so:
20p(p+1
We calculate terms in parentheses: -(20p(p+1), so:
20p(p+1
We calculate terms in parentheses: -(20p(p+1), so:
20p(p+1
We calculate terms in parentheses: -(20p(p+1), so:
20p(p+1
We calculate terms in parentheses: -(20p(p+1), so:
20p(p+1
We calculate terms in parentheses: -(20p(p+1), so:
20p(p+1
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20p(p+1
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20p(p+1
We calculate terms in parentheses: -(20p(p+1), so:
20p(p+1
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20p(p+1
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20p(p+1
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