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10=1/3(9x+30)+2
We move all terms to the left:
10-(1/3(9x+30)+2)=0
Domain of the equation: 3(9x+30)+2)!=0We multiply all the terms by the denominator
x∈R
-(1+10*3(9x+30)+2)=0
We calculate terms in parentheses: -(1+10*3(9x+30)+2), so:We add all the numbers together, and all the variables
1+10*3(9x+30)+2
determiningTheFunctionDomain 10*3(9x+30)+1+2
We add all the numbers together, and all the variables
10*3(9x+30)+3
Wy multiply elements
30x(9+3
Back to the equation:
-(30x(9+3)
-(30x12=0
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