10=12-4(x+2)+2x

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Solution for 10=12-4(x+2)+2x equation: 



10=12-4(x+2)+2x

We move all terms to the left:

10-(12-4(x+2)+2x)=0



We calculate terms in parentheses: -(12-4(x+2)+2x), so:

12-4(x+2)+2x

determiningTheFunctionDomain
-4(x+2)+2x+12

We add all the numbers together, and all the variables

2x-4(x+2)+12

We multiply parentheses

2x-4x-8+12

We add all the numbers together, and all the variables

-2x+4

Back to the equation:

-(-2x+4)



We get rid of parentheses

2x-4+10=0

We add all the numbers together, and all the variables

2x+6=0

We move all terms containing x to the left, all other terms to the right

2x=-6

x=-6/2

x=-3

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