10=142/(5+q)

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Solution for 10=142/(5+q) equation: 



10=142/(5+q)

We move all terms to the left:

10-(142/(5+q))=0



Domain of the equation: (5+q))!=0

We move all terms containing q to the left, all other terms to the right

q)!=-5

q!=-5/1

q!=-5

q∈R



We add all the numbers together, and all the variables

-(142/(q+5))+10=0

We multiply all the terms by the denominator


-(142+10*(q+5))=0



We calculate terms in parentheses: -(142+10*(q+5)), so:

142+10*(q+5)

determiningTheFunctionDomain
10*(q+5)+142

We multiply parentheses

10q+50+142

We add all the numbers together, and all the variables

10q+192

Back to the equation:

-(10q+192)



We get rid of parentheses

-10q-192=0

We move all terms containing q to the left, all other terms to the right

-10q=192

q=192/-10

q=-19+1/5

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