10=2(1/2a+5)

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Solution for 10=2(1/2a+5) equation: 



10=2(1/2a+5)

We move all terms to the left:

10-(2(1/2a+5))=0



Domain of the equation: 2a+5))!=0

a∈R



We multiply all the terms by the denominator


-(2(1+10*2a+5))=0



We calculate terms in parentheses: -(2(1+10*2a+5)), so:

2(1+10*2a+5)

We add all the numbers together, and all the variables

2(10*2a+6)

We multiply parentheses

40a+12

Back to the equation:

-(40a+12)



We get rid of parentheses

-40a-12=0

We move all terms containing a to the left, all other terms to the right

-40a=12

a=12/-40

a=-3/10

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