10=2(5-a)

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Solution for 10=2(5-a) equation: 



10=2(5-a)

We move all terms to the left:

10-(2(5-a))=0

We add all the numbers together, and all the variables

-(2(-1a+5))+10=0



We calculate terms in parentheses: -(2(-1a+5)), so:

2(-1a+5)

We multiply parentheses

-2a+10

Back to the equation:

-(-2a+10)



We get rid of parentheses

2a-10+10=0

We add all the numbers together, and all the variables

2a=0

a=0/2

a=0

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