10=2(5-x)+5(3-x)

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Solution for 10=2(5-x)+5(3-x) equation: 



10=2(5-x)+5(3-x)

We move all terms to the left:

10-(2(5-x)+5(3-x))=0

We add all the numbers together, and all the variables

-(2(-1x+5)+5(-1x+3))+10=0



We calculate terms in parentheses: -(2(-1x+5)+5(-1x+3)), so:

2(-1x+5)+5(-1x+3)

We multiply parentheses

-2x-5x+10+15

We add all the numbers together, and all the variables

-7x+25

Back to the equation:

-(-7x+25)



We get rid of parentheses

7x-25+10=0

We add all the numbers together, and all the variables

7x-15=0

We move all terms containing x to the left, all other terms to the right

7x=15

x=15/7

x=2+1/7

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