10=2(66-2x)+2x

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Solution for 10=2(66-2x)+2x equation: 



10=2(66-2x)+2x

We move all terms to the left:

10-(2(66-2x)+2x)=0

We add all the numbers together, and all the variables

-(2(-2x+66)+2x)+10=0



We calculate terms in parentheses: -(2(-2x+66)+2x), so:

2(-2x+66)+2x

We add all the numbers together, and all the variables

2x+2(-2x+66)

We multiply parentheses

2x-4x+132

We add all the numbers together, and all the variables

-2x+132

Back to the equation:

-(-2x+132)



We get rid of parentheses

2x-132+10=0

We add all the numbers together, and all the variables

2x-122=0

We move all terms containing x to the left, all other terms to the right

2x=122

x=122/2

x=61

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