10=2(b+3)+2

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Solution for 10=2(b+3)+2 equation: 



10=2(b+3)+2

We move all terms to the left:

10-(2(b+3)+2)=0



We calculate terms in parentheses: -(2(b+3)+2), so:

2(b+3)+2

We multiply parentheses

2b+6+2

We add all the numbers together, and all the variables

2b+8

Back to the equation:

-(2b+8)



We get rid of parentheses

-2b-8+10=0

We add all the numbers together, and all the variables

-2b+2=0

We move all terms containing b to the left, all other terms to the right

-2b=-2

b=-2/-2

b=1

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