10=2(j+1)+1

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Solution for 10=2(j+1)+1 equation:



10=2(j+1)+1
We move all terms to the left:
10-(2(j+1)+1)=0
We calculate terms in parentheses: -(2(j+1)+1), so:
2(j+1)+1
We multiply parentheses
2j+2+1
We add all the numbers together, and all the variables
2j+3
Back to the equation:
-(2j+3)
We get rid of parentheses
-2j-3+10=0
We add all the numbers together, and all the variables
-2j+7=0
We move all terms containing j to the left, all other terms to the right
-2j=-7
j=-7/-2
j=3+1/2

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