10=2(j-51)

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Solution for 10=2(j-51) equation: 



10=2(j-51)

We move all terms to the left:

10-(2(j-51))=0



We calculate terms in parentheses: -(2(j-51)), so:

2(j-51)

We multiply parentheses

2j-102

Back to the equation:

-(2j-102)



We get rid of parentheses

-2j+102+10=0

We add all the numbers together, and all the variables

-2j+112=0

We move all terms containing j to the left, all other terms to the right

-2j=-112

j=-112/-2

j=+56

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