10=2(k-6)

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Solution for 10=2(k-6) equation:



10=2(k-6)
We move all terms to the left:
10-(2(k-6))=0
We calculate terms in parentheses: -(2(k-6)), so:
2(k-6)
We multiply parentheses
2k-12
Back to the equation:
-(2k-12)
We get rid of parentheses
-2k+12+10=0
We add all the numbers together, and all the variables
-2k+22=0
We move all terms containing k to the left, all other terms to the right
-2k=-22
k=-22/-2
k=+11

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