10=2/3(3x+9)

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Solution for 10=2/3(3x+9) equation: 



10=2/3(3x+9)

We move all terms to the left:

10-(2/3(3x+9))=0



Domain of the equation: 3(3x+9))!=0

x∈R



We multiply all the terms by the denominator


-(2+10*3(3x+9))=0



We calculate terms in parentheses: -(2+10*3(3x+9)), so:

2+10*3(3x+9)

determiningTheFunctionDomain
10*3(3x+9)+2

Wy multiply elements

30x(3+2

Back to the equation:

-(30x(3+2)



We add all the numbers together, and all the variables

-(30x5=0

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