10=2/5(3a+10)

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Solution for 10=2/5(3a+10) equation: 



10=2/5(3a+10)

We move all terms to the left:

10-(2/5(3a+10))=0



Domain of the equation: 5(3a+10))!=0

a∈R



We multiply all the terms by the denominator


-(2+10*5(3a+10))=0



We calculate terms in parentheses: -(2+10*5(3a+10)), so:

2+10*5(3a+10)

determiningTheFunctionDomain
10*5(3a+10)+2

Wy multiply elements

50a(3+2

Back to the equation:

-(50a(3+2)



We add all the numbers together, and all the variables

-(50a5=0

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