10=3(c+2)+1

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Solution for 10=3(c+2)+1 equation: 



10=3(c+2)+1

We move all terms to the left:

10-(3(c+2)+1)=0



We calculate terms in parentheses: -(3(c+2)+1), so:

3(c+2)+1

We multiply parentheses

3c+6+1

We add all the numbers together, and all the variables

3c+7

Back to the equation:

-(3c+7)



We get rid of parentheses

-3c-7+10=0

We add all the numbers together, and all the variables

-3c+3=0

We move all terms containing c to the left, all other terms to the right

-3c=-3

c=-3/-3

c=1

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