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10=3+b/2b=
We move all terms to the left:
10-(3+b/2b)=0
Domain of the equation: 2b)!=0We add all the numbers together, and all the variables
b!=0/1
b!=0
b∈R
-(b/2b+3)+10=0
We get rid of parentheses
-b/2b-3+10=0
We multiply all the terms by the denominator
-b-3*2b+10*2b=0
We add all the numbers together, and all the variables
-1b-3*2b+10*2b=0
Wy multiply elements
-1b-6b+20b=0
We add all the numbers together, and all the variables
13b=0
b=0/13
b=0
Równanie nie ma rozwiązania
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