10=3x+4(4x+20)

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Solution for 10=3x+4(4x+20) equation:



10=3x+4(4x+20)
We move all terms to the left:
10-(3x+4(4x+20))=0
We calculate terms in parentheses: -(3x+4(4x+20)), so:
3x+4(4x+20)
We multiply parentheses
3x+16x+80
We add all the numbers together, and all the variables
19x+80
Back to the equation:
-(19x+80)
We get rid of parentheses
-19x-80+10=0
We add all the numbers together, and all the variables
-19x-70=0
We move all terms containing x to the left, all other terms to the right
-19x=70
x=70/-19
x=-3+13/19

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