10=4(20a-5)+10a

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Solution for 10=4(20a-5)+10a equation: 



10=4(20a-5)+10a

We move all terms to the left:

10-(4(20a-5)+10a)=0



We calculate terms in parentheses: -(4(20a-5)+10a), so:

4(20a-5)+10a

We add all the numbers together, and all the variables

10a+4(20a-5)

We multiply parentheses

10a+80a-20

We add all the numbers together, and all the variables

90a-20

Back to the equation:

-(90a-20)



We get rid of parentheses

-90a+20+10=0

We add all the numbers together, and all the variables

-90a+30=0

We move all terms containing a to the left, all other terms to the right

-90a=-30

a=-30/-90

a=1/3

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