10=4+3(r+2)

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Solution for 10=4+3(r+2) equation: 



10=4+3(r+2)

We move all terms to the left:

10-(4+3(r+2))=0



We calculate terms in parentheses: -(4+3(r+2)), so:

4+3(r+2)

determiningTheFunctionDomain
3(r+2)+4

We multiply parentheses

3r+6+4

We add all the numbers together, and all the variables

3r+10

Back to the equation:

-(3r+10)



We get rid of parentheses

-3r-10+10=0

We add all the numbers together, and all the variables

-3r=0

r=0/-3

r=0

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