10=4+3(t+2,)

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Solution for 10=4+3(t+2,) equation: 



10=4+3(t+2.)

We move all terms to the left:

10-(4+3(t+2.))=0

We add all the numbers together, and all the variables

-(4+3(t+2))+10=0



We calculate terms in parentheses: -(4+3(t+2)), so:

4+3(t+2)

determiningTheFunctionDomain
3(t+2)+4

We multiply parentheses

3t+6+4

We add all the numbers together, and all the variables

3t+10

Back to the equation:

-(3t+10)



We get rid of parentheses

-3t-10+10=0

We add all the numbers together, and all the variables

-3t=0

t=0/-3

t=0

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