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10=40+1/5x
We move all terms to the left:
10-(40+1/5x)=0
Domain of the equation: 5x)!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
-(1/5x+40)+10=0
We get rid of parentheses
-1/5x-40+10=0
We multiply all the terms by the denominator
-40*5x+10*5x-1=0
Wy multiply elements
-200x+50x-1=0
We add all the numbers together, and all the variables
-150x-1=0
We move all terms containing x to the left, all other terms to the right
-150x=1
x=1/-150
x=-1/150
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