10=6(1m-2)-8

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Solution for 10=6(1m-2)-8 equation: 



10=6(1m-2)-8

We move all terms to the left:

10-(6(1m-2)-8)=0

We add all the numbers together, and all the variables

-(6(m-2)-8)+10=0



We calculate terms in parentheses: -(6(m-2)-8), so:

6(m-2)-8

We multiply parentheses

6m-12-8

We add all the numbers together, and all the variables

6m-20

Back to the equation:

-(6m-20)



We get rid of parentheses

-6m+20+10=0

We add all the numbers together, and all the variables

-6m+30=0

We move all terms containing m to the left, all other terms to the right

-6m=-30

m=-30/-6

m=+5

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