10=6(y+2)-8y

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Solution for 10=6(y+2)-8y equation: 



10=6(y+2)-8y

We move all terms to the left:

10-(6(y+2)-8y)=0



We calculate terms in parentheses: -(6(y+2)-8y), so:

6(y+2)-8y

We add all the numbers together, and all the variables

-8y+6(y+2)

We multiply parentheses

-8y+6y+12

We add all the numbers together, and all the variables

-2y+12

Back to the equation:

-(-2y+12)



We get rid of parentheses

2y-12+10=0

We add all the numbers together, and all the variables

2y-2=0

We move all terms containing y to the left, all other terms to the right

2y=2

y=2/2

y=1

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