10=8(3y-4)-33y+20

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Solution for 10=8(3y-4)-33y+20 equation: 



10=8(3y-4)-33y+20

We move all terms to the left:

10-(8(3y-4)-33y+20)=0



We calculate terms in parentheses: -(8(3y-4)-33y+20), so:

8(3y-4)-33y+20

We add all the numbers together, and all the variables

-33y+8(3y-4)+20

We multiply parentheses

-33y+24y-32+20

We add all the numbers together, and all the variables

-9y-12

Back to the equation:

-(-9y-12)



We get rid of parentheses

9y+12+10=0

We add all the numbers together, and all the variables

9y+22=0

We move all terms containing y to the left, all other terms to the right

9y=-22

y=-22/9

y=-2+4/9

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