10=9/5(y-32)

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Solution for 10=9/5(y-32) equation: 



10=9/5(y-32)

We move all terms to the left:

10-(9/5(y-32))=0



Domain of the equation: 5(y-32))!=0

y∈R



We multiply all the terms by the denominator


-(9+10*5(y-32))=0



We calculate terms in parentheses: -(9+10*5(y-32)), so:

9+10*5(y-32)

determiningTheFunctionDomain
10*5(y-32)+9

Wy multiply elements

50y(y+9

Back to the equation:

-(50y(y+9)





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