10=b2/3

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Solution for 10=b2/3 equation: 


b in (-oo:+oo)

10 = (b^2)/3 // - (b^2)/3

10-((b^2)/3) = 0

-1/3*b^2 = -10 // : -1/3

b^2 = 30

b^2 = 30 // ^ 1/2

abs(b) = 30^(1/2)

b = 30^(1/2) or b = -30^(1/2)

b in { 30^(1/2), -30^(1/2) }

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