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10=x+9/x
We move all terms to the left:
10-(x+9/x)=0
Domain of the equation: x)!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
-(+x+9/x)+10=0
We get rid of parentheses
-x-9/x+10=0
We multiply all the terms by the denominator
-x*x+10*x-9=0
We add all the numbers together, and all the variables
10x-x*x-9=0
Wy multiply elements
-1x^2+10x-9=0
a = -1; b = 10; c = -9;
Δ = b2-4ac
Δ = 102-4·(-1)·(-9)
Δ = 64
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{64}=8$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(10)-8}{2*-1}=\frac{-18}{-2} =+9 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(10)+8}{2*-1}=\frac{-2}{-2} =1 $
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