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10X^2+10X+12=72
We move all terms to the left:
10X^2+10X+12-(72)=0
We add all the numbers together, and all the variables
10X^2+10X-60=0
a = 10; b = 10; c = -60;
Δ = b2-4ac
Δ = 102-4·10·(-60)
Δ = 2500
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{2500}=50$$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(10)-50}{2*10}=\frac{-60}{20} =-3 $$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(10)+50}{2*10}=\frac{40}{20} =2 $
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