10X2+4y2+12=10

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Solution for 10X2+4y2+12=10 equation: 



10X^2+4X^2+12=10

We move all terms to the left:

10X^2+4X^2+12-(10)=0

We add all the numbers together, and all the variables

14X^2+2=0

a = 14; b = 0; c = +2;
Δ = b2-4ac
Δ = 02-4·14·2
Δ = -112
Delta is less than zero, so there is no solution for the equation

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