10a2+27a-837=0

Solution for 10a2+27a-837=0 equation:

10a^2+27a-837=0

a = 10; b = 27; c = -837;
Δ = b2-4ac
Δ = 272-4·10·(-837)
Δ = 34209
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{34209}=\sqrt{9*3801}=\sqrt{9}*\sqrt{3801}=3\sqrt{3801}$
$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(27)-3\sqrt{3801}}{2*10}=\frac{-27-3\sqrt{3801}}{20}
$
$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(27)+3\sqrt{3801}}{2*10}=\frac{-27+3\sqrt{3801}}{20}
$