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10a^2-10=630
We move all terms to the left:
10a^2-10-(630)=0
We add all the numbers together, and all the variables
10a^2-640=0
a = 10; b = 0; c = -640;
Δ = b2-4ac
Δ = 02-4·10·(-640)
Δ = 25600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{25600}=160$$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-160}{2*10}=\frac{-160}{20} =-8 $$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+160}{2*10}=\frac{160}{20} =8 $
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