10a=3(3a-4)=15

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Solution for 10a=3(3a-4)=15 equation: 



10a=3(3a-4)=15

We move all terms to the left:

10a-(3(3a-4))=0



We calculate terms in parentheses: -(3(3a-4)), so:

3(3a-4)

We multiply parentheses

9a-12

Back to the equation:

-(9a-12)



We get rid of parentheses

10a-9a+12=0

We add all the numbers together, and all the variables

a+12=0

We move all terms containing a to the left, all other terms to the right

a=-12

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