10b+10+10=10(b-6)-4(b-6)

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Solution for 10b+10+10=10(b-6)-4(b-6) equation: 



10b+10+10=10(b-6)-4(b-6)

We move all terms to the left:

10b+10+10-(10(b-6)-4(b-6))=0

We add all the numbers together, and all the variables

10b-(10(b-6)-4(b-6))+20=0



We calculate terms in parentheses: -(10(b-6)-4(b-6)), so:

10(b-6)-4(b-6)

We multiply parentheses

10b-4b-60+24

We add all the numbers together, and all the variables

6b-36

Back to the equation:

-(6b-36)



We get rid of parentheses

10b-6b+36+20=0

We add all the numbers together, and all the variables

4b+56=0

We move all terms containing b to the left, all other terms to the right

4b=-56

b=-56/4

b=-14

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