10b-45=3(b-1)

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Solution for 10b-45=3(b-1) equation: 



10b-45=3(b-1)

We move all terms to the left:

10b-45-(3(b-1))=0



We calculate terms in parentheses: -(3(b-1)), so:

3(b-1)

We multiply parentheses

3b-3

Back to the equation:

-(3b-3)



We get rid of parentheses

10b-3b+3-45=0

We add all the numbers together, and all the variables

7b-42=0

We move all terms containing b to the left, all other terms to the right

7b=42

b=42/7

b=6

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