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10b-45=3(b-1)
We move all terms to the left:
10b-45-(3(b-1))=0
We calculate terms in parentheses: -(3(b-1)), so:We get rid of parentheses
3(b-1)
We multiply parentheses
3b-3
Back to the equation:
-(3b-3)
10b-3b+3-45=0
We add all the numbers together, and all the variables
7b-42=0
We move all terms containing b to the left, all other terms to the right
7b=42
b=42/7
b=6
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