10b2=27b-18

Solution for 10b2=27b-18 equation:

10b^2=27b-18

We move all terms to the left:

10b^2-(27b-18)=0

We get rid of parentheses

10b^2-27b+18=0

a = 10; b = -27; c = +18;
Δ = b2-4ac
Δ = -272-4·10·18
Δ = 9
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{9}=3$
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-27)-3}{2*10}=\frac{24}{20}
=1+1/5
$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-27)+3}{2*10}=\frac{30}{20}
=1+1/2
$