10c+128=8c+100

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Solution for 10c+128=8c+100 equation:


Simplifying
10c + 128 = 8c + 100

Reorder the terms:
128 + 10c = 8c + 100

Reorder the terms:
128 + 10c = 100 + 8c

Solving
128 + 10c = 100 + 8c

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-8c' to each side of the equation.
128 + 10c + -8c = 100 + 8c + -8c

Combine like terms: 10c + -8c = 2c
128 + 2c = 100 + 8c + -8c

Combine like terms: 8c + -8c = 0
128 + 2c = 100 + 0
128 + 2c = 100

Add '-128' to each side of the equation.
128 + -128 + 2c = 100 + -128

Combine like terms: 128 + -128 = 0
0 + 2c = 100 + -128
2c = 100 + -128

Combine like terms: 100 + -128 = -28
2c = -28

Divide each side by '2'.
c = -14

Simplifying
c = -14

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