10c+15=67(2c+3)

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Solution for 10c+15=67(2c+3) equation:



10c+15=67(2c+3)
We move all terms to the left:
10c+15-(67(2c+3))=0
We calculate terms in parentheses: -(67(2c+3)), so:
67(2c+3)
We multiply parentheses
134c+201
Back to the equation:
-(134c+201)
We get rid of parentheses
10c-134c-201+15=0
We add all the numbers together, and all the variables
-124c-186=0
We move all terms containing c to the left, all other terms to the right
-124c=186
c=186/-124
c=-1+1/2

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