10c+35-4c=7c+28

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Solution for 10c+35-4c=7c+28 equation: 



10c+35-4c=7c+28

We move all terms to the left:

10c+35-4c-(7c+28)=0

We add all the numbers together, and all the variables

6c-(7c+28)+35=0

We get rid of parentheses

6c-7c-28+35=0

We add all the numbers together, and all the variables

-1c+7=0

We move all terms containing c to the left, all other terms to the right

-c=-7

c=-7/-1

c=+7

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