10c+3c+4=2(2c-1)+24

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Solution for 10c+3c+4=2(2c-1)+24 equation: 



10c+3c+4=2(2c-1)+24

We move all terms to the left:

10c+3c+4-(2(2c-1)+24)=0

We add all the numbers together, and all the variables

13c-(2(2c-1)+24)+4=0



We calculate terms in parentheses: -(2(2c-1)+24), so:

2(2c-1)+24

We multiply parentheses

4c-2+24

We add all the numbers together, and all the variables

4c+22

Back to the equation:

-(4c+22)



We get rid of parentheses

13c-4c-22+4=0

We add all the numbers together, and all the variables

9c-18=0

We move all terms containing c to the left, all other terms to the right

9c=18

c=18/9

c=2

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