10c+7=3(c-8)-5+10c

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Solution for 10c+7=3(c-8)-5+10c equation: 



10c+7=3(c-8)-5+10c

We move all terms to the left:

10c+7-(3(c-8)-5+10c)=0



We calculate terms in parentheses: -(3(c-8)-5+10c), so:

3(c-8)-5+10c

determiningTheFunctionDomain
3(c-8)+10c-5

We add all the numbers together, and all the variables

10c+3(c-8)-5

We multiply parentheses

10c+3c-24-5

We add all the numbers together, and all the variables

13c-29

Back to the equation:

-(13c-29)



We get rid of parentheses

10c-13c+29+7=0

We add all the numbers together, and all the variables

-3c+36=0

We move all terms containing c to the left, all other terms to the right

-3c=-36

c=-36/-3

c=+12

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