10c-3(5c-1)=2(4c+3)-5c

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Solution for 10c-3(5c-1)=2(4c+3)-5c equation: 



10c-3(5c-1)=2(4c+3)-5c

We move all terms to the left:

10c-3(5c-1)-(2(4c+3)-5c)=0

We multiply parentheses

10c-15c-(2(4c+3)-5c)+3=0



We calculate terms in parentheses: -(2(4c+3)-5c), so:

2(4c+3)-5c

We add all the numbers together, and all the variables

-5c+2(4c+3)

We multiply parentheses

-5c+8c+6

We add all the numbers together, and all the variables

3c+6

Back to the equation:

-(3c+6)



We add all the numbers together, and all the variables

-5c-(3c+6)+3=0

We get rid of parentheses

-5c-3c-6+3=0

We add all the numbers together, and all the variables

-8c-3=0

We move all terms containing c to the left, all other terms to the right

-8c=3

c=3/-8

c=-3/8

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