10c-3(5c-1)=2(4c+3)-5c

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Solution for 10c-3(5c-1)=2(4c+3)-5c equation:



10c-3(5c-1)=2(4c+3)-5c
We move all terms to the left:
10c-3(5c-1)-(2(4c+3)-5c)=0
We multiply parentheses
10c-15c-(2(4c+3)-5c)+3=0
We calculate terms in parentheses: -(2(4c+3)-5c), so:
2(4c+3)-5c
We add all the numbers together, and all the variables
-5c+2(4c+3)
We multiply parentheses
-5c+8c+6
We add all the numbers together, and all the variables
3c+6
Back to the equation:
-(3c+6)
We add all the numbers together, and all the variables
-5c-(3c+6)+3=0
We get rid of parentheses
-5c-3c-6+3=0
We add all the numbers together, and all the variables
-8c-3=0
We move all terms containing c to the left, all other terms to the right
-8c=3
c=3/-8
c=-3/8

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