10c-7-2c=4c-c+28

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Solution for 10c-7-2c=4c-c+28 equation: 



10c-7-2c=4c-c+28

We move all terms to the left:

10c-7-2c-(4c-c+28)=0

We add all the numbers together, and all the variables

10c-2c-(3c+28)-7=0

We add all the numbers together, and all the variables

8c-(3c+28)-7=0

We get rid of parentheses

8c-3c-28-7=0

We add all the numbers together, and all the variables

5c-35=0

We move all terms containing c to the left, all other terms to the right

5c=35

c=35/5

c=7

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