10c2-80c+160=0

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Solution for 10c2-80c+160=0 equation: 



10c^2-80c+160=0

a = 10; b = -80; c = +160;
Δ = b2-4ac
Δ = -802-4·10·160
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$c=\frac{-b}{2a}=\frac{80}{20}=4$

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