10d-1/3(-3-9d)=40

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Solution for 10d-1/3(-3-9d)=40 equation: 



10d-1/3(-3-9d)=40

We move all terms to the left:

10d-1/3(-3-9d)-(40)=0



Domain of the equation: 3(-3-9d)!=0

d∈R



We add all the numbers together, and all the variables

10d-1/3(-9d-3)-40=0

We multiply all the terms by the denominator


10d*3(-9d-3)-40*3(-9d-3)-1=0

Wy multiply elements

30d^2(--120d(--1=0

We use the square of the difference formula

30d^2(+120d(+1=0

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