10f-12=20+2f

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Solution for 10f-12=20+2f equation: 



10f-12=20+2f

We move all terms to the left:

10f-12-(20+2f)=0

We add all the numbers together, and all the variables

10f-(2f+20)-12=0

We get rid of parentheses

10f-2f-20-12=0

We add all the numbers together, and all the variables

8f-32=0

We move all terms containing f to the left, all other terms to the right

8f=32

f=32/8

f=4

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