10g2+6g=72

Solution for 10g2+6g=72 equation:

10g^2+6g=72

We move all terms to the left:

10g^2+6g-(72)=0

a = 10; b = 6; c = -72;
Δ = b2-4ac
Δ = 62-4·10·(-72)
Δ = 2916
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$g_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$g_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{2916}=54$
$g_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(6)-54}{2*10}=\frac{-60}{20}
=-3
$
$g_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(6)+54}{2*10}=\frac{48}{20}
=2+2/5
$